Q1) \(x + 3\over 2\) + \(x + 9\over 7\) = [ \(9 x + 39\over 14\) ]

Q1) \(10\over x+ 2\) - \(6\over x +4\) = [ \(4 x + 28\over x^{2}+ 6 x +8 \)]

Q1) \(10\over x+ 3\) + \(3\over x -10\) = [ \(13 x -91\over x^{2}-7x -30 \)]

Q2) \(x + 9\over 4\) + \(x + 7\over 2\) = [ \(3 x + 23\over 4\) ]

Q2) \(9\over x+ 5\) - \(7\over x +6\) = [ \(2 x + 19\over x^{2}+ 11x +30 \)]

Q2) \(10\over x+ 9\) - \(3\over x -2\) = [ \(7 x -47\over x^{2}+7x -18 \)]

Q3) \(x + 9\over 5\) + \(x + 5\over 4\) = [ \(9 x + 61\over 20\) ]

Q3) \(9\over x+ 7\) + \(10\over x +8\) = [ \(19 x + 142\over x^{2}+ 15 x +56 \)]

Q3) \(8\over x+ 3\) - \(4\over x +3\) = [ \(4 x + 12\over x^{2}+6x +9 \)]

Q4) \(x + 9\over 4\) - \(x + 10\over 7\) = [ \(3 x + 23\over 28\) ]

Q4) \(8\over x+ 6\) - \(4\over x +3\) = [ \(4 x\over x^{2}+ 9 x +18 \)]

Q4) \(6\over x+ 4\) + \(9\over x -3\) = [ \(15 x + 18\over x^{2}+x -12 \)]

Q5) \(x + 8\over 2\) - \(x + 9\over 5\) = [ \(3 x + 22\over 10\) ]

Q5) \(7\over x+ 2\) + \(9\over x +5\) = [ \(16 x + 53\over x^{2}+ 7 x +10 \)]

Q5) \(8\over x+ 4\) - \(4\over x -6\) = [ \(4 x -64\over x^{2}-2x -24 \)]

Q6) \(x + 8\over 2\) - \(x + 10\over 8\) = [ \(3 x + 22\over 8\) ]

Q6) \(10\over x+ 3\) - \(8\over x +4\) = [ \(2 x + 16\over x^{2}+ 7 x +12 \)]

Q6) \(9\over x+ 4\) + \(8\over x +6\) = [ \(17 x + 86\over x^{2}+10x +24 \)]

Q7) \(x + 6\over 4\) - \(x + 8\over 7\) = [ \(3 x + 10\over 28\) ]

Q7) \(10\over x+ 6\) + \(5\over x +3\) = [ \(15 x + 60\over x^{2}+ 9 x +18 \)]

Q7) \(9\over x+ 6\) - \(7\over x -6\) = [ \(2 x -96\over x^{2} -36 \)]

Q8) \(x + 10\over 5\) + \(x + 9\over 8\) = [ \(13 x + 125\over 40\) ]

Q8) \(6\over x+ 2\) + \(10\over x +2\) = [ \(16 x + 32\over x^{2}+ 4 x +4 \)]

Q8) \(9\over x+ 4\) - \(2\over x -7\) = [ \(7 x -71\over x^{2}-3x -28 \)]

Q9) \(x + 6\over 2\) + \(x + 3\over 2\) = [ \(2 x + 9\over 2\) ]

Q9) \(10\over x+ 3\) + \(7\over x +2\) = [ \(17 x + 41\over x^{2}+ 5 x +6 \)]

Q9) \(10\over x+ 3\) - \(5\over x +4\) = [ \(5 x + 25\over x^{2}+7x +12 \)]

Q10) \(x + 3\over 2\) + \(x + 8\over 4\) = [ \(3 x + 14\over 4\) ]

Q10) \(9\over x+ 3\) - \(7\over x +3\) = [ \(2 x + 6\over x^{2}+ 6 x +9 \)]

Q10) \(5\over x+ 4\) + \(8\over x -10\) = [ \(13 x -18\over x^{2}-6x -40 \)]