Q1) \(x + 8\over 5\) + \(x + 9\over 5\) = [ \(2 x + 17\over 5\) ]

Q1) \(10\over x+ 4\) - \(6\over x +4\) = [ \(4 x + 16\over x^{2}+ 8 x +16 \)]

Q1) \(7\over x+ 4\) + \(8\over x -3\) = [ \(15 x + 11\over x^{2}+x -12 \)]

Q2) \(x + 7\over 2\) - \(x + 9\over 5\) = [ \(3 x + 17\over 10\) ]

Q2) \(6\over x+ 4\) - \(4\over x +2\) = [ \(2 x -4\over x^{2}+ 6 x +8 \)]

Q2) \(7\over x+ 3\) - \(5\over x -6\) = [ \(2 x -57\over x^{2}-3x -18 \)]

Q3) \(x + 9\over 2\) - \(x + 7\over 5\) = [ \(3 x + 31\over 10\) ]

Q3) \(8\over x+ 7\) + \(8\over x +3\) = [ \(16 x + 80\over x^{2}+ 10 x +21 \)]

Q3) \(9\over x+ 5\) - \(6\over x -3\) = [ \(3 x -57\over x^{2}+2x -15 \)]

Q4) \(x + 5\over 2\) + \(x + 6\over 2\) = [ \(2 x + 11\over 2\) ]

Q4) \(7\over x+ 4\) + \(4\over x +3\) = [ \(11x + 37\over x^{2}+ 7 x +12 \)]

Q4) \(10\over x+ 3\) - \(5\over x -9\) = [ \(5 x -105\over x^{2}-6x -27 \)]

Q5) \(x + 5\over 2\) - \(x + 8\over 5\) = [ \(3 x + 9\over 10\) ]

Q5) \(10\over x+ 2\) - \(4\over x +3\) = [ \(6 x + 22\over x^{2}+ 5 x +6 \)]

Q5) \(10\over x+ 6\) - \(8\over x +5\) = [ \(2 x + 2\over x^{2}+11x +30 \)]

Q6) \(x + 3\over 2\) + \(x + 5\over 3\) = [ \(5 x + 19\over 6\) ]

Q6) \(8\over x+ 2\) - \(6\over x +3\) = [ \(2 x + 12\over x^{2}+ 5 x +6 \)]

Q6) \(7\over x+ 5\) + \(9\over x -10\) = [ \(16 x -25\over x^{2}-5x -50 \)]

Q7) \(x + 4\over 2\) - \(x + 10\over 7\) = [ \(5 x + 8\over 14\) ]

Q7) \(10\over x+ 9\) - \(4\over x +3\) = [ \(6 x -6\over x^{2}+ 12 x +27 \)]

Q7) \(6\over x+ 2\) + \(2\over x -3\) = [ \(8 x -14\over x^{2}-x -6 \)]

Q8) \(x + 7\over 2\) - \(x + 10\over 8\) = [ \(3 x + 18\over 8\) ]

Q8) \(10\over x+ 4\) - \(6\over x +2\) = [ \(4 x -4\over x^{2}+ 6 x +8 \)]

Q8) \(10\over x+ 4\) - \(5\over x -3\) = [ \(5 x -50\over x^{2}+x -12 \)]

Q9) \(x + 7\over 4\) - \(x + 10\over 9\) = [ \(5 x + 23\over 36\) ]

Q9) \(10\over x+ 3\) - \(7\over x +4\) = [ \(3 x + 19\over x^{2}+ 7 x +12 \)]

Q9) \(8\over x+ 5\) + \(10\over x +5\) = [ \(18 x + 90\over x^{2}+10x +25 \)]

Q10) \(x + 10\over 3\) - \(x + 9\over 7\) = [ \(4 x + 43\over 21\) ]

Q10) \(8\over x+ 3\) - \(5\over x +2\) = [ \(3 x + 1\over x^{2}+ 5 x +6 \)]

Q10) \(8\over x+ 2\) - \(3\over x -4\) = [ \(5 x -38\over x^{2}-2x -8 \)]