Mr Daniels Maths
Conversions: Mixed to Improper fractions

Set 1

Set 2

Set 3

Q1) 5\(\frac{1}{2}\)= [ \(11\over2\) ]

Q1) 7\(\frac{1}{5}\)= [ \(36\over5\) ]

Q1) 5\(\frac{1}{11}\)= [ \(56\over11\) ]

Q2) 3\(\frac{2}{3}\)= [ \(11\over3\) ]

Q2) 4\(\frac{5}{6}\)= [ \(29\over6\) ]

Q2) 13\(\frac{1}{8}\)= [ \(105\over8\) ]

Q3) 5\(\frac{2}{3}\)= [ \(17\over3\) ]

Q3) 10\(\frac{5}{6}\)= [ \(65\over6\) ]

Q3) 7\(\frac{7}{11}\)= [ \(84\over11\) ]

Q4) 6\(\frac{1}{3}\)= [ \(19\over3\) ]

Q4) 12\(\frac{1}{5}\)= [ \(61\over5\) ]

Q4) 6\(\frac{1}{8}\)= [ \(49\over8\) ]

Q5) 5\(\frac{1}{3}\)= [ \(16\over3\) ]

Q5) 8\(\frac{1}{6}\)= [ \(49\over6\) ]

Q5) 14\(\frac{7}{9}\)= [ \(133\over9\) ]

Q6) 4\(\frac{2}{3}\)= [ \(14\over3\) ]

Q6) 9\(\frac{3}{5}\)= [ \(48\over5\) ]

Q6) 6\(\frac{5}{12}\)= [ \(77\over12\) ]

Q7) 3\(\frac{1}{3}\)= [ \(10\over3\) ]

Q7) 10\(\frac{2}{5}\)= [ \(52\over5\) ]

Q7) 4\(\frac{5}{11}\)= [ \(49\over11\) ]

Q8) 4\(\frac{1}{3}\)= [ \(13\over3\) ]

Q8) 12\(\frac{4}{5}\)= [ \(64\over5\) ]

Q8) 3\(\frac{8}{9}\)= [ \(35\over9\) ]

Q9) 6\(\frac{2}{3}\)= [ \(20\over3\) ]

Q9) 7\(\frac{5}{6}\)= [ \(47\over6\) ]

Q9) 4\(\frac{1}{12}\)= [ \(49\over12\) ]

Q10) 6\(\frac{1}{2}\)= [ \(13\over2\) ]

Q10) 8\(\frac{3}{5}\)= [ \(43\over5\) ]

Q10) 9\(\frac{1}{10}\)= [ \(91\over10\) ]