Mr Daniels Maths
Difference of two squares

Set 1

Set 2

Set 3

Q1) Expand \((x+8)(x-8)\) = [ \(x^2 - 64\)]

Q1) Factorise \(x^2 - 36\)= [ \((x+6)(x-6)\)]

Q1) Factorise \(100x^2-25\)= [ \((10x + 5)(10x - 5)\)]

Q2) Expand \((x+5)(x-5)\) = [ \(x^2 - 25\)]

Q2) Factorise \(x^2 - 144\)= [ \((x+12)(x-12)\)]

Q2) Factorise \(4x^2-64\)= [ \((2x + 8)(2x - 8)\)]

Q3) Expand \((x+10)(x-10)\) = [ \(x^2 - 100\)]

Q3) Factorise \(x^2 - 289\)= [ \((x+17)(x-17)\)]

Q3) Factorise \(36x^2-81\)= [ \((6x + 9)(6x - 9)\)]

Q4) Expand \((x+9)(x-9)\) = [ \(x^2 - 81\)]

Q4) Factorise \(x^2 - 81\)= [ \((x+9)(x-9)\)]

Q4) Factorise \(100x^2-64\)= [ \((10x + 8)(10x - 8)\)]

Q5) Expand \((x+1)(x-1)\) = [ \(x^2 - 1\)]

Q5) Factorise \(x^2 - 256\)= [ \((x+16)(x-16)\)]

Q5) Factorise \(81x^2-9\)= [ \((9x + 3)(9x - 3)\)]

Q6) Expand \((x+6)(x-6)\) = [ \(x^2 - 36\)]

Q6) Factorise \(x^2 - 64\)= [ \((x+8)(x-8)\)]

Q6) Factorise \(64x^2-49\)= [ \((8x + 7)(8x - 7)\)]

Q7) Expand \((x+4)(x-4)\) = [ \(x^2 - 16\)]

Q7) Factorise \(x^2 - 361\)= [ \((x+19)(x-19)\)]

Q7) Factorise \(4x^2-100\)= [ \((2x + 10)(2x - 10)\)]

Q8) Expand \((x+2)(x-2)\) = [ \(x^2 - 4\)]

Q8) Factorise \(x^2 - 100\)= [ \((x+10)(x-10)\)]

Q8) Factorise \(9x^2-1\)= [ \((3x + 1)(3x - 1)\)]

Q9) Expand \((x+7)(x-7)\) = [ \(x^2 - 49\)]

Q9) Factorise \(x^2 - 49\)= [ \((x+7)(x-7)\)]

Q9) Factorise \(49x^2-64\)= [ \((7x + 8)(7x - 8)\)]

Q10) Expand \((x+3)(x-3)\) = [ \(x^2 - 9\)]

Q10) Factorise \(x^2 - 400\)= [ \((x+20)(x-20)\)]

Q10) Factorise \(100x^2-100\)= [ \((10x + 10)(10x - 10)\)]