Mr Daniels Maths
Fraction Subtraction

Set 1

Set 2

Set 3

Q1) \(\frac{3}{4}\) - \(\frac{1}{2}\) = [ \(\frac{1}{4}\)]

Q1) 1\(\frac{1}{3}\) - \(\frac{3}{5}\) = [ \(\frac{11}{15}\)]

Q1) 3\(\frac{1}{4}\) - 1\(\frac{1}{6}\) = [ 2\(\frac{1}{12}\)]

Q2) \(\frac{3}{4}\) - \(\frac{3}{5}\) = [ \(\frac{3}{20}\)]

Q2) 1\(\frac{1}{2}\) - \(\frac{5}{6}\) = [ \(\frac{2}{3}\)]

Q2) 4\(\frac{1}{2}\) - 1\(\frac{5}{9}\) = [ 2\(\frac{17}{18}\)]

Q3) \(\frac{1}{2}\) - \(\frac{2}{5}\) = [ \(\frac{1}{10}\)]

Q3) 1\(\frac{1}{2}\) - \(\frac{2}{3}\) = [ \(\frac{5}{6}\)]

Q3) 4\(\frac{1}{3}\) - 1\(\frac{8}{9}\) = [ 2\(\frac{4}{9}\)]

Q4) \(\frac{3}{4}\) - \(\frac{2}{3}\) = [ \(\frac{1}{12}\)]

Q4) 1\(\frac{2}{3}\) - \(\frac{3}{4}\) = [ \(\frac{11}{12}\)]

Q4) 2\(\frac{4}{5}\) - 1\(\frac{9}{10}\) = [ \(\frac{9}{10}\)]

Q5) \(\frac{2}{5}\) - \(\frac{1}{3}\) = [ \(\frac{1}{15}\)]

Q5) 1\(\frac{1}{6}\) - \(\frac{2}{3}\) = [ \(\frac{1}{2}\)]

Q5) 3\(\frac{1}{3}\) - 1\(\frac{3}{5}\) = [ 1\(\frac{11}{15}\)]

Q6) \(\frac{3}{4}\) - \(\frac{3}{7}\) = [ \(\frac{9}{28}\)]

Q6) 1\(\frac{3}{7}\) - \(\frac{2}{3}\) = [ \(\frac{16}{21}\)]

Q6) 2\(\frac{1}{3}\) - 1\(\frac{3}{5}\) = [ \(\frac{11}{15}\)]

Q7) \(\frac{8}{9}\) - \(\frac{3}{4}\) = [ \(\frac{5}{36}\)]

Q7) 1\(\frac{3}{5}\) - \(\frac{3}{4}\) = [ \(\frac{17}{20}\)]

Q7) 2\(\frac{3}{7}\) - 2\(\frac{2}{5}\) = [ \(\frac{1}{35}\)]

Q8) \(\frac{1}{2}\) - \(\frac{2}{7}\) = [ \(\frac{3}{14}\)]

Q8) 1\(\frac{2}{5}\) - \(\frac{6}{7}\) = [ \(\frac{19}{35}\)]

Q8) 4\(\frac{1}{2}\) - 2\(\frac{3}{4}\) = [ 1\(\frac{3}{4}\)]

Q9) \(\frac{2}{3}\) - \(\frac{3}{5}\) = [ \(\frac{1}{15}\)]

Q9) 1\(\frac{2}{5}\) - \(\frac{3}{4}\) = [ \(\frac{13}{20}\)]

Q9) 3\(\frac{1}{2}\) - 1\(\frac{2}{5}\) = [ 2\(\frac{1}{10}\)]

Q10) \(\frac{2}{3}\) - \(\frac{1}{2}\) = [ \(\frac{1}{6}\)]

Q10) 1\(\frac{1}{3}\) - \(\frac{2}{3}\) = [ \(\frac{2}{3}\)]

Q10) 2\(\frac{1}{2}\) - 1\(\frac{4}{9}\) = [ 1\(\frac{1}{18}\)]