Mr Daniels Maths
Mixed and Improper Conversions

Set 1

Set 2

Set 3

Q1) 5\(\frac{2}{3}\)= [ \(17\over3\) ]

Q1) 11\(\frac{4}{5}\)= [ \(59\over5\) ]

Q1) 13\(\frac{3}{10}\)= [ \(133\over10\) ]

Q2) 5\(\frac{1}{2}\)= [ \(11\over2\) ]

Q2) 8\(\frac{4}{5}\)= [ \(44\over5\) ]

Q2) 10\(\frac{1}{9}\)= [ \(91\over9\) ]

Q3) 6\(\frac{2}{3}\)= [ \(20\over3\) ]

Q3) 10\(\frac{3}{5}\)= [ \(53\over5\) ]

Q3) 6\(\frac{1}{8}\)= [ \(49\over8\) ]

Q4) 3\(\frac{2}{3}\)= [ \(11\over3\) ]

Q4) 5\(\frac{5}{6}\)= [ \(35\over6\) ]

Q4) 9\(\frac{6}{11}\)= [ \(105\over11\) ]

Q5) 4\(\frac{2}{3}\)= [ \(14\over3\) ]

Q5) 6\(\frac{3}{5}\)= [ \(33\over5\) ]

Q5) 3\(\frac{1}{9}\)= [ \(28\over9\) ]

Q6) 6\(\frac{1}{3}\)= [ \(19\over3\) ]

Q6) 8\(\frac{1}{5}\)= [ \(41\over5\) ]

Q6) 16\(\frac{5}{8}\)= [ \(133\over8\) ]

Q7) 4\(\frac{1}{3}\)= [ \(13\over3\) ]

Q7) 6\(\frac{1}{5}\)= [ \(31\over5\) ]

Q7) 3\(\frac{9}{11}\)= [ \(42\over11\) ]

Q8) 5\(\frac{1}{3}\)= [ \(16\over3\) ]

Q8) 4\(\frac{5}{6}\)= [ \(29\over6\) ]

Q8) 4\(\frac{1}{12}\)= [ \(49\over12\) ]

Q9) 6\(\frac{1}{2}\)= [ \(13\over2\) ]

Q9) 10\(\frac{1}{6}\)= [ \(61\over6\) ]

Q9) 6\(\frac{2}{9}\)= [ \(56\over9\) ]

Q10) 3\(\frac{1}{3}\)= [ \(10\over3\) ]

Q10) 9\(\frac{1}{6}\)= [ \(55\over6\) ]

Q10) 7\(\frac{7}{8}\)= [ \(63\over8\) ]