Mr Daniels Maths
Mixed and Improper Conversions

Set 1

Set 2

Set 3

Q1) 6\(\frac{1}{2}\)= [ \(13\over2\) ]

Q1) 8\(\frac{3}{5}\)= [ \(43\over5\) ]

Q1) 7\(\frac{7}{8}\)= [ \(63\over8\) ]

Q2) 4\(\frac{1}{3}\)= [ \(13\over3\) ]

Q2) 10\(\frac{1}{5}\)= [ \(51\over5\) ]

Q2) 9\(\frac{1}{10}\)= [ \(91\over10\) ]

Q3) 5\(\frac{1}{3}\)= [ \(16\over3\) ]

Q3) 11\(\frac{3}{5}\)= [ \(58\over5\) ]

Q3) 15\(\frac{5}{9}\)= [ \(140\over9\) ]

Q4) 5\(\frac{1}{2}\)= [ \(11\over2\) ]

Q4) 13\(\frac{4}{5}\)= [ \(69\over5\) ]

Q4) 9\(\frac{11}{12}\)= [ \(119\over12\) ]

Q5) 3\(\frac{1}{3}\)= [ \(10\over3\) ]

Q5) 8\(\frac{2}{5}\)= [ \(42\over5\) ]

Q5) 10\(\frac{8}{9}\)= [ \(98\over9\) ]

Q6) 3\(\frac{2}{3}\)= [ \(11\over3\) ]

Q6) 10\(\frac{3}{5}\)= [ \(53\over5\) ]

Q6) 4\(\frac{9}{10}\)= [ \(49\over10\) ]

Q7) 6\(\frac{2}{3}\)= [ \(20\over3\) ]

Q7) 12\(\frac{1}{5}\)= [ \(61\over5\) ]

Q7) 7\(\frac{7}{12}\)= [ \(91\over12\) ]

Q8) 6\(\frac{1}{3}\)= [ \(19\over3\) ]

Q8) 9\(\frac{3}{5}\)= [ \(48\over5\) ]

Q8) 3\(\frac{8}{9}\)= [ \(35\over9\) ]

Q9) 4\(\frac{2}{3}\)= [ \(14\over3\) ]

Q9) 9\(\frac{1}{6}\)= [ \(55\over6\) ]

Q9) 11\(\frac{5}{11}\)= [ \(126\over11\) ]

Q10) 5\(\frac{2}{3}\)= [ \(17\over3\) ]

Q10) 5\(\frac{4}{5}\)= [ \(29\over5\) ]

Q10) 12\(\frac{8}{11}\)= [ \(140\over11\) ]