Mr Daniels Maths
Solving Equations 3 Brackets

Set 1

Set 2

Set 3

Q1) \( {x\over3}+6 = 10\) [ \(x= 12\)]

Q1) \(7(z + 2) = 63\) [ z= \(7\)]

Q1) 6(4z + 3) = 66 [ z = 2]

Q2) \(8x -5 = 35\) [ \( x = 5\)]

Q2) \(9(y + 3) = 81\) [ y= \(6\)]

Q2) 3(2y -10) = -12 [ y = 3]

Q3) \( {z\over8}+3 = 7\) [ \(z= 32\)]

Q3) \(10(y + 4) = 100\) [ y= \(6\)]

Q3) 8(2x -2) = 32 [ x = 3]

Q4) \(4y -6 = 6\) [ \( y = 3\)]

Q4) \(2(z -5) = 2\) [ z= \(6\)]

Q4) 2(10w -5) = 50 [ w = 3]

Q5) \(4x + 3 = 23\) [ \( x = 5\)]

Q5) \(3(z + 9) = 39\) [ z= \(4\)]

Q5) 2(8z -9) = 62 [ z = 5]

Q6) \( {w\over10}+5 = 13\) [ \(w= 80\)]

Q6) \(8(x -6) = 16\) [ x= \(8\)]

Q6) 3(3x -3) = 9 [ x = 2]

Q7) \(5y -9 = 41\) [ \( y = 10\)]

Q7) \(8(x -2) = 40\) [ x= \(7\)]

Q7) 6(3z + 6) = 72 [ z = 2]

Q8) \(7z -9 = 19\) [ \( z = 4\)]

Q8) \(10(y -9) = 10\) [ y= \(10\)]

Q8) 2(5w + 4) = 58 [ w = 5]

Q9) \(14z + 10 = 150\) [ \( z = 10\)]

Q9) \(6(x + 7) = 78\) [ x= \(6\)]

Q9) 7(8y -3) = 91 [ y = 2]

Q10) \(12w + 3 = 51\) [ \( w = 4\)]

Q10) \(5(y -6) = 15\) [ y= \(9\)]

Q10) 3(3x + 2) = 42 [ x = 4]