Mr Daniels Maths
Surds Simplifying

Set 1

Set 2

Set 3

Q1) \(\sqrt{18}\) = [ \(3\sqrt{2}\)]

Q1) \(2\sqrt 7 \) x \(2\sqrt 8= \) [ \(8\sqrt{14}\)]

Q1) \(\sqrt { 500 } \) - \(\sqrt { 80 }= \) [ \(6\sqrt{5}\)]

Q2) \(\sqrt{45}\) = [ \(3\sqrt{5}\)]

Q2) \(4\sqrt 8 \) x \(2\sqrt 7= \) [ \(16\sqrt{14}\)]

Q2) \(\sqrt { 20 } \) + \(\sqrt { 180 }= \) [ \(8\sqrt{5}\)]

Q3) \(\sqrt{360}\) = [ \(6\sqrt{10}\)]

Q3) \(8 \sqrt 54 \over{ 4 \sqrt 6} \) = [ \(6\)]

Q3) \(\sqrt { 245 } \) + \(\sqrt { 80 }= \) [ \(11\sqrt{5}\)]

Q4) \(\sqrt{28}\) = [ \(2\sqrt{7}\)]

Q4) \(2\sqrt 8 \) x \(3\sqrt 7= \) [ \(12\sqrt{14}\)]

Q4) \(\sqrt { 405 } \) + \(\sqrt { 45 }= \) [ \(12\sqrt{5}\)]

Q5) \(\sqrt{96}\) = [ \(4\sqrt{6}\)]

Q5) \(4\sqrt 6 \) x \(3\sqrt 2= \) [ \(24\sqrt{3}\)]

Q5) \(\sqrt { 192 } \) + \(\sqrt { 192 }= \) [ \(16\sqrt{3}\)]

Q6) \(\sqrt{40}\) = [ \(2\sqrt{10}\)]

Q6) \(16 \sqrt 21 \over{ 4 \sqrt 7} \) = [ \(4\sqrt{3}\)]

Q6) \(\sqrt { 98 } \) + \(\sqrt { 98 }= \) [ \(14\sqrt{2}\)]

Q7) \(\sqrt{8}\) = [ \(2\sqrt{2}\)]

Q7) \(20 \sqrt 60 \over{ 5 \sqrt 10} \) = [ \(4\sqrt{6}\)]

Q7) \(\sqrt { 75 } \) - \(\sqrt { 3 }= \) [ \(4\sqrt{3}\)]

Q8) \(\sqrt{24}\) = [ \(2\sqrt{6}\)]

Q8) \(8 \sqrt 49 \over{ 4 \sqrt 7} \) = [ \(2\sqrt{7}\)]

Q8) \(\sqrt { 245 } \) - \(\sqrt { 20 }= \) [ \(5\sqrt{5}\)]

Q9) \(\sqrt{150}\) = [ \(5\sqrt{6}\)]

Q9) \(5\sqrt 7 \) x \(5\sqrt 5= \) [ \(25\sqrt{35}\)]

Q9) \(\sqrt { 12 } \) + \(\sqrt { 192 }= \) [ \(10\sqrt{3}\)]

Q10) \(\sqrt{252}\) = [ \(6\sqrt{7}\)]

Q10) \(20 \sqrt 16 \over{ 5 \sqrt 8} \) = [ \(4\sqrt{2}\)]

Q10) \(\sqrt { 12 } \) + \(\sqrt { 48 }= \) [ \(6\sqrt{3}\)]