Mr Daniels Maths
Surds Simplifying

Set 1

Set 2

Set 3

Q1) \(\sqrt{252}\) = [ \(6\sqrt{7}\)]

Q1) \(4\sqrt 4 \) x \(4\sqrt 1= \) [ \(32\)]

Q1) \(\sqrt { 20 } \) + \(\sqrt { 405 }= \) [ \(11\sqrt{5}\)]

Q2) \(\sqrt{50}\) = [ \(5\sqrt{2}\)]

Q2) \(6 \sqrt 36 \over{ 2 \sqrt 6} \) = [ \(3\sqrt{6}\)]

Q2) \(\sqrt { 125 } \) + \(\sqrt { 245 }= \) [ \(12\sqrt{5}\)]

Q3) \(\sqrt{72}\) = [ \(6\sqrt{2}\)]

Q3) \(20 \sqrt 14 \over{ 4 \sqrt 7} \) = [ \(5\sqrt{2}\)]

Q3) \(\sqrt { 98 } \) - \(\sqrt { 50 }= \) [ \(2\sqrt{2}\)]

Q4) \(\sqrt{150}\) = [ \(5\sqrt{6}\)]

Q4) \(3\sqrt 2 \) x \(2\sqrt 2= \) [ \(12\)]

Q4) \(\sqrt { 320 } \) + \(\sqrt { 245 }= \) [ \(15\sqrt{5}\)]

Q5) \(\sqrt{40}\) = [ \(2\sqrt{10}\)]

Q5) \(4 \sqrt 45 \over{ 2 \sqrt 9} \) = [ \(2\sqrt{5}\)]

Q5) \(\sqrt { 300 } \) - \(\sqrt { 3 }= \) [ \(9\sqrt{3}\)]

Q6) \(\sqrt{20}\) = [ \(2\sqrt{5}\)]

Q6) \(12 \sqrt 5 \over{ 3 \sqrt 1} \) = [ \(4\sqrt{5}\)]

Q6) \(\sqrt { 98 } \) - \(\sqrt { 72 }= \) [ \(\sqrt{2}\)]

Q7) \(\sqrt{28}\) = [ \(2\sqrt{7}\)]

Q7) \(25 \sqrt 3 \over{ 5 \sqrt 3} \) = [ \(5\)]

Q7) \(\sqrt { 245 } \) + \(\sqrt { 500 }= \) [ \(17\sqrt{5}\)]

Q8) \(\sqrt{24}\) = [ \(2\sqrt{6}\)]

Q8) \(6 \sqrt 70 \over{ 3 \sqrt 7} \) = [ \(2\sqrt{10}\)]

Q8) \(\sqrt { 75 } \) - \(\sqrt { 12 }= \) [ \(3\sqrt{3}\)]

Q9) \(\sqrt{80}\) = [ \(4\sqrt{5}\)]

Q9) \(3\sqrt 6 \) x \(5\sqrt 6= \) [ \(90\)]

Q9) \(\sqrt { 162 } \) - \(\sqrt { 50 }= \) [ \(4\sqrt{2}\)]

Q10) \(\sqrt{48}\) = [ \(4\sqrt{3}\)]

Q10) \(25 \sqrt 5 \over{ 5 \sqrt 5} \) = [ \(5\)]

Q10) \(\sqrt { 405 } \) - \(\sqrt { 320 }= \) [ \(\sqrt{5}\)]